Răspuns:
Explicație pas cu pas:
x(x+3)=[tex]x^{2}[/tex]+3x -5+5 =0+5=5
(x+1)(x+2)=[tex]x^{2}[/tex] +3x+2 -5+5=[tex]x^{2}[/tex] + 3x -5+7 =0+7
A(x)=5·7=35
[tex]\it x^2+3x-5=0 \Rightarrow x^2+3x=5\ \ \ \ \ (*)\\ \\ A(x)=x(x+1)(x+2)(x+3)=\bigg[x(x+3)\bigg]\bigg[(x+1)(x+2)\bigg]=\\ \\ \\ =(x^2+3x)(x^2+3x+2)\ \stackrel{(*)}{=}5\cdot(5+2)=5\cdot7=35[/tex]
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Răspuns:
Explicație pas cu pas:
x(x+3)=[tex]x^{2}[/tex]+3x -5+5 =0+5=5
(x+1)(x+2)=[tex]x^{2}[/tex] +3x+2 -5+5=[tex]x^{2}[/tex] + 3x -5+7 =0+7
A(x)=5·7=35
[tex]\it x^2+3x-5=0 \Rightarrow x^2+3x=5\ \ \ \ \ (*)\\ \\ A(x)=x(x+1)(x+2)(x+3)=\bigg[x(x+3)\bigg]\bigg[(x+1)(x+2)\bigg]=\\ \\ \\ =(x^2+3x)(x^2+3x+2)\ \stackrel{(*)}{=}5\cdot(5+2)=5\cdot7=35[/tex]