Răspuns:
Explicație pas cu pas:
(x²+x)(x²+x+2)+1 =
x(x+1)(x(x+1) + 2) + 1 =
x^2(x+1)^2 + 2x(X+1) + 1 =
(x(x+1) + 1)^2 =
(x(x+1) + 1)(x(x+1) + 1) =
(x^2 + x + 1)(x^2 + x + 1).
[tex]\it E= (x^2+x)(x^2+x+2)+1\\ \\ Not\breve am\ x^2+x=t,\ iar\ expresia\ devine:\\ \\ E=t(t+2)+1=t^2+2t+1=(t+1)^2\\ \\ Revenim\ asupra\ nota\c{\it t}iei\ \d si\ vom\ avea:\\ \\ E=(x^2+x+1)^2[/tex]
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Răspuns:
Explicație pas cu pas:
(x²+x)(x²+x+2)+1 =
x(x+1)(x(x+1) + 2) + 1 =
x^2(x+1)^2 + 2x(X+1) + 1 =
(x(x+1) + 1)^2 =
(x(x+1) + 1)(x(x+1) + 1) =
(x^2 + x + 1)(x^2 + x + 1).
[tex]\it E= (x^2+x)(x^2+x+2)+1\\ \\ Not\breve am\ x^2+x=t,\ iar\ expresia\ devine:\\ \\ E=t(t+2)+1=t^2+2t+1=(t+1)^2\\ \\ Revenim\ asupra\ nota\c{\it t}iei\ \d si\ vom\ avea:\\ \\ E=(x^2+x+1)^2[/tex]