Explicație pas cu pas:
a)
[tex]\Big(\dfrac{^{2)} 4 \sqrt{5} }{5} - \dfrac{^{ \sqrt{5})} 3}{2 \sqrt{5} }\Big) : \Big( - \dfrac{ \sqrt{20} }{3} \Big) = \Big(\dfrac{8 \sqrt{5} - 3 \sqrt{5} }{10}\Big) : \Big( - \dfrac{ 2\sqrt{5} }{3} \Big) = \dfrac{5 \sqrt{5} ^{(5} }{10} \cdot \Big( - \dfrac{3}{2\sqrt{5}} \Big) = - \dfrac{\sqrt{5}}{2} \cdot \dfrac{3}{2\sqrt{5}} = - \dfrac{3}{4} [/tex]
d)
[tex]\dfrac{^{ \sqrt{2})} 1}{3 \sqrt{2} } + \dfrac{^{ \sqrt{6})}5 \sqrt{2} }{ \sqrt{6} } = \dfrac{ \sqrt{2} }{3 \cdot 2} + \dfrac{5 \sqrt{2 \cdot 6} }{6} = \dfrac{ \sqrt{2} + 5 \sqrt{ {2}^{2} \cdot 3} }{6} = \dfrac{ \sqrt{2} + 5 \cdot 2 \sqrt{3} }{6} = \dfrac{ \sqrt{2} + 10 \sqrt{3} }{6}[/tex]
e)
[tex]\dfrac{ \sqrt{30} }{2} \Big( \sqrt{5} - \dfrac{3}{2 \sqrt{5} } \Big) = \dfrac{ \sqrt{30} }{2} \Big( ^{10)} \sqrt{5} - \dfrac{^{ \sqrt{5} )} 3}{2 \sqrt{5} } \Big) = \dfrac{ \sqrt{30} }{2} \cdot \dfrac{10 \sqrt{5} - 3 \sqrt{5} }{2 \cdot 5} = \dfrac{ \sqrt{30} \cdot 7 \sqrt{5} }{20} = \dfrac{7 \sqrt{30 \cdot 5} }{20} = \dfrac{7 \cdot 5 \sqrt{6}^{(5} }{20} = \dfrac{7 \sqrt{6}}{4}[/tex]
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Explicație pas cu pas:
a)
[tex]\Big(\dfrac{^{2)} 4 \sqrt{5} }{5} - \dfrac{^{ \sqrt{5})} 3}{2 \sqrt{5} }\Big) : \Big( - \dfrac{ \sqrt{20} }{3} \Big) = \Big(\dfrac{8 \sqrt{5} - 3 \sqrt{5} }{10}\Big) : \Big( - \dfrac{ 2\sqrt{5} }{3} \Big) = \dfrac{5 \sqrt{5} ^{(5} }{10} \cdot \Big( - \dfrac{3}{2\sqrt{5}} \Big) = - \dfrac{\sqrt{5}}{2} \cdot \dfrac{3}{2\sqrt{5}} = - \dfrac{3}{4} [/tex]
d)
[tex]\dfrac{^{ \sqrt{2})} 1}{3 \sqrt{2} } + \dfrac{^{ \sqrt{6})}5 \sqrt{2} }{ \sqrt{6} } = \dfrac{ \sqrt{2} }{3 \cdot 2} + \dfrac{5 \sqrt{2 \cdot 6} }{6} = \dfrac{ \sqrt{2} + 5 \sqrt{ {2}^{2} \cdot 3} }{6} = \dfrac{ \sqrt{2} + 5 \cdot 2 \sqrt{3} }{6} = \dfrac{ \sqrt{2} + 10 \sqrt{3} }{6}[/tex]
e)
[tex]\dfrac{ \sqrt{30} }{2} \Big( \sqrt{5} - \dfrac{3}{2 \sqrt{5} } \Big) = \dfrac{ \sqrt{30} }{2} \Big( ^{10)} \sqrt{5} - \dfrac{^{ \sqrt{5} )} 3}{2 \sqrt{5} } \Big) = \dfrac{ \sqrt{30} }{2} \cdot \dfrac{10 \sqrt{5} - 3 \sqrt{5} }{2 \cdot 5} = \dfrac{ \sqrt{30} \cdot 7 \sqrt{5} }{20} = \dfrac{7 \sqrt{30 \cdot 5} }{20} = \dfrac{7 \cdot 5 \sqrt{6}^{(5} }{20} = \dfrac{7 \sqrt{6}}{4}[/tex]