Calculati: [tex]\sqrt{3^2+} \frac{3^4}{2^4}[/tex]
[tex]\sqrt{7^2+} \[tex]\sqrt{7^2+\frac{7^2*4^2}{3^2} }[/tex]
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Răspuns:
[tex]\sqrt{3^{2} +\frac{3^{4} }{2^{4} } } = \frac{15}{4}[/tex]
[tex]\sqrt{7^{2} +\frac{7^{2} *4^{2} }{3^{2} } } = \frac{35}{3}[/tex]
Explicație pas cu pas:
[tex]\sqrt{3^{2}+\frac{3^{4} }{2^{4} } } = \sqrt{9+\frac{81}{16} } = \sqrt{\frac{9*16+81}{16} } = \sqrt{\frac{225}{16} } = \frac{15}{4}[/tex]
[tex]\sqrt{7^{2} +\frac{7^{2} +4^{2} }{3^{2} } } = \sqrt{49+\frac{49*16}{9} } = \sqrt{\frac{49*9+784}{9} } = \sqrt{\frac{1225}{9} } = \frac{35}{3}[/tex]