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x-1 ≠0 x≠1
(x³+2x²-x-2)/(x²+7x+6)=[x²(x+2)-(x+2)]/(x+1)(x+6)=(x+2)(x²-1)/(x+1)(x+6)=
=(x+2)(x-1)(x+1)/(x+1)(x+6)=(x+2)(x-1)/(x+6)
x+6 ≠0 x≠-6