Efectuati:
a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat)
b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)*[(rad13-rad11)^3]^2;
c)1/2-rad3 x^2 -3+[1/2+rad3 *x^2+3(1-x)]
d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q
Multumesc mult!
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=[(16x^4-16x^4]:(0,05(36)xy^2)^3=
=0:(0,05(36)xy^2)^3=0
c)
1/(2-√3 ) × x^2 -3+[1/(2+√3) × *x^2+3(1-x)]=
=x^2(2+√3)/(2-√3)(2+√3)-3+[x^2(2-√3)/(2+√3)(2-√3) +3-3x]=
=(2x^2+x^2√3)/(4-3)-3+[2x^2-x^2√3)/(4-3)+3-3x]=
=2x^2+x^2√3-3+2x^2-x^2√3+3-3x=
=4x^2-3x=
=x(4x-3)
d)[(√23x-√21)*(√23x+√21)]^40 :[(23x^2-21)^8]^5=
=(23x^2-21)^40 :(23x^2-21)^40=0