February 2019 1 73 Report
Sa se arate ca:
a) \frac{cos12+ \sqrt{3}sin12 }{cos3-sin3}= \sqrt{2}
b) \frac{cos5+sin25}{cos25-sin5} = \sqrt{3}
c) sin^{4} \frac{ \pi }{8} + sin^{4} \frac{ 3\pi }{8} + sin^{4} \frac{5 \pi }{8} + sin^{4} \frac{ 7\pi }{8} = \frac{3}{2}
d) cos^{4} \frac{ \pi }{8} + cos^{4} \frac{ 3\pi }{8} + cos^{4} \frac{5 \pi }{8} + cos^{4} \frac{ 7\pi }{8} = \frac{3}{2}
e)sin20*sin40*sin60*sin80= \frac{3}{16}
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Efectuati: a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat) b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)*[(rad13-rad11)^3]^2; c)1/2-rad3 x^2 -3+[1/2+rad3 *x^2+3(1-x)] d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q Multumesc mult!
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Calculati: Multumesc mult!
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Sa se verifice egalitatile: a)sin4x+2sin2x=4sin2x* b) c) d)
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Sa se arate ca: a) b) c) d) e)Acel A cu caciulita arata ca acolo sunt grade (cos12grade,sin12grade...)si el nu se afla in enunt.Multumesc mult!
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Sa se demonstreze ca daca intre laturile triunghiului ABC exista relatia abc(a+b+c)=16,triunghiul este echilateral.Multumesc mult!
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