Verified answer

Răspuns:

1. 195g Zn; 294g H₂SO₄

2. 112g Fe

Explicație:

1.

M(H₂SO₄) = 2 × A(H) + A(S) + 4 × A(O) = 2 × 1 + 32 + 4 × 16 = 98 g/mol

M(H₂) = 2 × A(H) = 2 × 1 = 2 g/mol

‍ ‍ ‍x‍ ‍ ‍ ‍‍ ‍‍ ‍ ‍‍ ‍ ‍ ‍y‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍‍ ‍ ‍6g

Zn + H₂SO₄ → ZnSO₄ + H₂↑

65g‍ ‍ ‍ ‍‍ ‍98g‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍2g

x = 65 × 6 : 2 = 195g Zn

y = 98 × 6 : 2 = 294g H₂SO₄

2.

M(FeCl₂) = A(Fe) + 2 × A(Cl) = 56 + 2 × 35,5 = 127 g/mol

‍ ‍‍ ‍x‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍254g

Fe + 2HCl → FeCl₂ + H₂↑

56g‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍127g

x = 56 × 254 : 127 = 112g Fe

-Mihai