A) · + =? b) · =? c) · d) Mulțumesc mult!Rezolvari complete va rog.... Idea question from @BlackSniper

January 2019 1 56 Report

A) $\frac{ x^{2}-7x+12 }{ x^{2} -16}$ · $\frac{x-2}{x-3}$ + $\frac{2x+14}{x+4}$ =?
b) $\frac{2}{x-2} + \frac{x+2}{x+1}$ · $( \frac{x-1}{x+2} - \frac{6}{x-2})$ =?
c) $\frac{x+2}{x+1}$ · $( \frac{x+1}{x+2} - \frac{ x^{2}-1 }{ x^{2} -4} ) + \frac{x-1}{x-2} =?$
d) $\frac{5x+6}{ x^{2} -4} - \frac{ x+3}{x-2} : \frac{ x^{2}+5x+6 }{x-2} = ?$
Mulțumesc mult!Rezolvari complete va rog...

renatemambouko A)
(x²-7x+12)/(x²-16) ×(x-2)/(x-3) +(2x+14)/(x+4) =
=(x²-4x-3x+12)/(x+4)(x-4) ×(x-2)/(x-3) +(2x+14)/(x+4) =
=[x(x-4)-3(x-4))/(x+4)(x-4) ×(x-2)/(x-3) +(2x+14)/(x+4) =
=(x-4)(x-3)/(x+4)(x-4) ×(x-2)/(x-3) +(2x+14)/(x+4) =
=(x-2)/(x+4) +(2x+14)/(x+4) =
=(3x+12)/(x+4)=
=3(x+4)/(x+4)=3

b)
2/(x-2)+(x+2)/(x+1)×[(x-1)/(x+2) - 6/(x-2)]=
=2/(x-2)+(x+2)/(x+1)×[(x-1)(x-2) - 6(x+2)]/(x²-4)=
=2/(x-2)+(x+2)/(x+1)×(x²-1x-2x+2 - 6x-12)/(x²-4)=
=2/(x-2)+(x+2)/(x+1)×(x²-9x-10)/(x²-4)=
=2/(x-2)+(x+2)/(x+1)×(x²-10x+x-10)/(x²-4)=
=2/(x-2)+(x+2)/(x+1)×[x(x-10)+(x-10)]/(x²-4)=
=2/(x-2)+(x+2)/(x+1)×(x-10)(x+1)/(x+2)(x-2)=
=2/(x-2)+(x-10)/(x-2)=
=(2+x-10)/(x-2)=(x-8)/(x-2)

c) (x+2)/(x+1) ×[(x+1)/(x+2) -(x²-1)/(x²-4)]+(x-1)/(x-2)=
=(x+2)/(x+1) ×[(x+1)(x-2) -(x²-1)]/(x²-4)+(x-1)/(x-2)=
=(x+2)/(x+1) ×(x²+x-2x-2 -x²+1)/(x+2)(x-2)+(x-1)/(x-2)=
=(x+2)/(x+1) ×(-x-1)/(x+2)(x-2)+(x-1)/(x-2)=
=(x+2)/(x+1) ×[-(x+1)]/(x+2)(x-2)+(x-1)/(x-2)=
=-1/(x-2)+(x-1)/(x-2)=
=(-1+x-1)/(x-2)=
=(x-2/(x-2)=1

d)
(5x+6)/(x²-4) -(x+3)/(x-2) : (x²+5x+6)/(x-2)=
=(5x+6)/(x²-4) -(x+3)/(x-2) ×(x-2)/(x²+2x+3x+6)=
=(5x+6)/(x²-4) -(x+3)/(x²+2x+3x+6)=
=(5x+6)/(x+2)(x-2) -(x+3)/ [x(x+2)+3(x+2)]=
=(5x+6)/(x+2)(x-2)- (x+3)/(x+3)(x+2)=
=(5x+6)/(x+2)(x-2)- 1/(x+2)=
=(5x+6- x+2)/(x+2)(x-2)=
=(4x+8)/(x+2)(x-2)=
=4(x+2)/(x+2)(x-2)=
=4/(x-2)
=(5x+6-(x²+3x+2x+6)]/(x+2)(x-2) × (x-2)/(x+2)(x+3)=
=(5x+6-x²-3x-2x-6)]/(x+2)(x-2) × (x-2)/(x+2)(x+3)=
=(-x²)/(x+2) × 1/(x+2)(x+3)=

Efectuati: a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat) b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)[(rad13-rad11)^3]^2; c)1/2-rad3 x^2 -3+[1/2+rad3 x^2+3(1-x)] d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q Multumesc mult!

Answer

BlackSniper February 2019 | 0 Replies

Calculati: Multumesc mult!

Answer

BlackSniper February 2019 | 0 Replies

Answer

BlackSniper February 2019 | 0 Replies

Answer

BlackSniper February 2019 | 0 Replies

Answer

BlackSniper February 2019 | 0 Replies

Answer

BlackSniper February 2019 | 0 Replies

Sa se verifice egalitatile: a)sin4x+2sin2x=4sin2x* b) c) d)

Answer

BlackSniper February 2019 | 0 Replies

Sa se arate ca: a) b) c) d) e)Acel A cu caciulita arata ca acolo sunt grade (cos12grade,sin12grade...)si el nu se afla in enunt.Multumesc mult!

Answer

BlackSniper February 2019 | 0 Replies

Sa se demonstreze ca daca intre laturile triunghiului ABC exista relatia abc(a+b+c)=16,triunghiul este echilateral.Multumesc mult!

Answer

Efectuati: a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat) b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)[(rad13-rad11)^3]^2; c)1/2-rad3 x^2 -3+[1/2+rad3 x^2+3(1-x)] d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q Multumesc mult!

Calculati: Multumesc mult!

Sa se verifice egalitatile: a)sin4x+2sin2x=4sin2x* b) c) d)

Sa se arate ca: a) b) c) d) e)Acel A cu caciulita arata ca acolo sunt grade (cos12grade,sin12grade...)si el nu se afla in enunt.Multumesc mult!

Sa se demonstreze ca daca intre laturile triunghiului ABC exista relatia abc(a+b+c)=16,triunghiul este echilateral.Multumesc mult!

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Efectuati: a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat) b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)*[(rad13-rad11)^3]^2; c)1/2-rad3 x^2 -3+[1/2+rad3 *x^2+3(1-x)] d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q Multumesc mult!

Calculati: Multumesc mult!

Sa se verifice egalitatile: a)sin4x+2sin2x=4sin2x* b) c) d)

Sa se arate ca: a) b) c) d) e)Acel A cu caciulita arata ca acolo sunt grade (cos12grade,sin12grade...)si el nu se afla in enunt.Multumesc mult!

Sa se demonstreze ca daca intre laturile triunghiului ABC exista relatia abc(a+b+c)=16,triunghiul este echilateral.Multumesc mult!

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Helpful Links

Smile Life

Get in touch

Efectuati: a)[(-2x)^4-2^4x^4]:(0,05(36)xy^2)^3;xy /=0; (egal taiat) b)(rad11/rad13-rad11 x+rad13/rad13-rad11 x)[(rad13-rad11)^3]^2; c)1/2-rad3 x^2 -3+[1/2+rad3 x^2+3(1-x)] d)[(rad23x-rad21)*(rad23x+rad21)]^40 :[(23x^2-21)^8]^5; x apartine lui Q Multumesc mult!