Răspuns:
-calculez moli si masa HBr din ecuatia reactiei
1mol............................2mol
H2 + Br2 ---> 2HBr
0,4mol...............................x
x=niu= 0,8molHBr
m,HBr= niuxmiu= 0,8(1+80)g=64,8g
-calculez masa de apa din masa solutiei in care s-a dizolvat 64,8gHBr
c=mdx100/ms-----> ms= mdx100/c= 64,8x100/6g=1080g
ms=md+m,apa----> m,apa= 1080g-64,8g=1015,2g
Explicație:
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Răspuns:
-calculez moli si masa HBr din ecuatia reactiei
1mol............................2mol
H2 + Br2 ---> 2HBr
0,4mol...............................x
x=niu= 0,8molHBr
m,HBr= niuxmiu= 0,8(1+80)g=64,8g
-calculez masa de apa din masa solutiei in care s-a dizolvat 64,8gHBr
c=mdx100/ms-----> ms= mdx100/c= 64,8x100/6g=1080g
ms=md+m,apa----> m,apa= 1080g-64,8g=1015,2g
Explicație: