se sting 2,5 Kg var.Calculati cati moli de produs final rezultata daca randamentul reactiei este de 92%.Va rog mult!
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Răspuns:
Explicație:
2,5kg CaO
randam. = 92%
masa de Ca(OH)2
randam. = mp.100 : mt
mp = randam. . mt : 100
mp= 92 . 2,5 : 100= 2,3 kg CaO
2,3kg xkg
CaO + H2 O= Ca(OH)2
56kg 74kg
x= 2,3 . 74 : 56 = 3, 04 kg Ca(OH)2
n= 3,04 kg : 74kg/kmoli= 0,041 kmoli Ca(OH)2
= 41moli
MCaO= 40 +16= 56 ------> 56kg/kmoli
MCa(OH)2= 40 + 2.16 +2=74-----> 74kg/kmoli