Varianta corectă este d) n³+n
[tex]S_{1} = 2 = 1 + 1[/tex]
[tex]\implies \boldsymbol{S_{1} = {1}^{3} + 1}\\[/tex]
[tex]S_{2} = 4 + 6 = 10 = 8 + 2 \\[/tex]
[tex]\implies \boldsymbol{S_{2} = {2}^{3} + 2}[/tex]
[tex]S_{3} = 8 + 10 + 12 = 30 = 27 + 3[/tex]
[tex]\implies \boldsymbol{S_{3} = {3}^{3} + 3}\\[/tex]
[tex]S_{4} = 14 + 16 + 18 + 20 = 68 = 64 + 4 \\ [/tex]
[tex]\implies \boldsymbol{S_{4} = {4}^{3} + 4}\\[/tex]
...
[tex]\implies \boldsymbol{S_{n} = {n}^{3} + n}\\[/tex]
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Varianta corectă este d) n³+n
[tex]S_{1} = 2 = 1 + 1[/tex]
[tex]\implies \boldsymbol{S_{1} = {1}^{3} + 1}\\[/tex]
[tex]S_{2} = 4 + 6 = 10 = 8 + 2 \\[/tex]
[tex]\implies \boldsymbol{S_{2} = {2}^{3} + 2}[/tex]
[tex]S_{3} = 8 + 10 + 12 = 30 = 27 + 3[/tex]
[tex]\implies \boldsymbol{S_{3} = {3}^{3} + 3}\\[/tex]
[tex]S_{4} = 14 + 16 + 18 + 20 = 68 = 64 + 4 \\ [/tex]
[tex]\implies \boldsymbol{S_{4} = {4}^{3} + 4}\\[/tex]
...
[tex]\implies \boldsymbol{S_{n} = {n}^{3} + n}\\[/tex]