Răspuns:
Explicație pas cu pas:
conform lui Pitagora in tr.BAC
AC= rad din ( 1600-1024)= 24 cm
A=semiprodusul catetelor= 24*32/2=24*16= 384 cm2
Raza cercului circumscris= BC/2=20 cm
BC=ipotenuza=diametrl cercului circumscris
c) r= S/p
s=aria tr.=384
p=semiperimetrul tr.=(40+32+24)/2= 48
r= 384/48= 8 cm
[tex]\it (3\cdot8;\ 4\cdot8;\ 5\cdot8) \Longrightarrow (24,\ \ 32,\ \ 40)\ -\ triplet \ pitagoreic \Rightarrow AC=24\ cm\\ \\ \\ \mathcal{A}=\dfrac{c_1\cdot c_2}{2}=\dfrac{24\cdot32}{2}=12\cdot32=...\\ \\ \\ R=BC:2=40:2=...\\ \\ \\ r=\dfrac{b+c-a}{2}=\dfrac{24+32-40}{2}=\dfrac{16}{2}=...[/tex]
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Răspuns:
Explicație pas cu pas:
conform lui Pitagora in tr.BAC
AC= rad din ( 1600-1024)= 24 cm
A=semiprodusul catetelor= 24*32/2=24*16= 384 cm2
Raza cercului circumscris= BC/2=20 cm
BC=ipotenuza=diametrl cercului circumscris
c) r= S/p
s=aria tr.=384
p=semiperimetrul tr.=(40+32+24)/2= 48
r= 384/48= 8 cm
Verified answer
[tex]\it (3\cdot8;\ 4\cdot8;\ 5\cdot8) \Longrightarrow (24,\ \ 32,\ \ 40)\ -\ triplet \ pitagoreic \Rightarrow AC=24\ cm\\ \\ \\ \mathcal{A}=\dfrac{c_1\cdot c_2}{2}=\dfrac{24\cdot32}{2}=12\cdot32=...\\ \\ \\ R=BC:2=40:2=...\\ \\ \\ r=\dfrac{b+c-a}{2}=\dfrac{24+32-40}{2}=\dfrac{16}{2}=...[/tex]