Răspuns:
MAl=27g/mol
MFe2O3=2x56+3x16=160g/mol
MFe=56g/mol
2x27....160g......................2x56g
2Al + Fe2O3 → Al2O3 + 2Fe
xg...........yg.........................112g
x=112x2x27/2x56=calculeaza
y=112x160/2x56=calculeaza
Explicație:
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Răspuns:
MAl=27g/mol
MFe2O3=2x56+3x16=160g/mol
MFe=56g/mol
2x27....160g......................2x56g
2Al + Fe2O3 → Al2O3 + 2Fe
xg...........yg.........................112g
x=112x2x27/2x56=calculeaza
y=112x160/2x56=calculeaza
Explicație: