[HO-] = 10la-3 mol/L
stim ca pOH = -lg[HO-] sau [HO-] = 10la-pOH = 10la-3
=> pOH = 3
stim ca pH + pOH = 14 => pH = 14-3 = 1
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[HO-] = 10la-3 mol/L
stim ca pOH = -lg[HO-] sau [HO-] = 10la-pOH = 10la-3
=> pOH = 3
stim ca pH + pOH = 14 => pH = 14-3 = 1