Calculati raportul atomic,raportul de masa si compozitia procentuala a celor 2 substante: SO2(dioxid de sulf) si MgCO3(carbonat de magneziu)
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Răspuns:
SO2
raport atomic=S:2O=1:2
raport de masa=S:O=32:32=1:1
compozitie procentuala
MSO2=32+2×16=64g/mol
64 gSO2..........32gS.............32 g O
100 gSO2.........X %S.............Y go
X=100×32/64=50 % S
Y=100×32/64=50 % O
MgCO3
raport atomic Mg:C:O=1:1:3
raoport de masa Mg:C:O=24:12:48=2:1:4
M=24+12+3*16=84g/mol
84g MgCO3..........24gMg.................12gC...............48gO
100g MgCO3..........X%Mg.................Y%C................Z%O
X=24×100/84=28,57% Mg
Y=12×100/84=14,28% C
Z=48×100/84=57,14% O
Explicație: