Răspuns:
Explicație:
220g CO2
react. cu Ba(OH)2
masa Ba(OH)2=?
xg 220g
Ba(OH)2 + CO2= BaCO3 + H2 O
171g 44g
x= 220 . 171 : 44 = 855g Ba(OH)2
n= m : M
MBa(OH)2= 137 + 2.16 + 2= 171---> 171g/moli
n= 855g : 171 g/moli = 5moli Ba(OH)2
MBa(OH)2= 137 + 2.16 + 2= 171g/moli
171g.............44g
xg...............220g
x= 220 x 171/ 44 = 855g Ba(OH)2
n= m /M
n= 855/171 = 5moli Ba(OH)2
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Răspuns:
Explicație:
220g CO2
react. cu Ba(OH)2
masa Ba(OH)2=?
xg 220g
Ba(OH)2 + CO2= BaCO3 + H2 O
171g 44g
x= 220 . 171 : 44 = 855g Ba(OH)2
n= m : M
MBa(OH)2= 137 + 2.16 + 2= 171---> 171g/moli
n= 855g : 171 g/moli = 5moli Ba(OH)2
Răspuns:
MBa(OH)2= 137 + 2.16 + 2= 171g/moli
171g.............44g
Ba(OH)2 + CO2= BaCO3 + H2 O
xg...............220g
x= 220 x 171/ 44 = 855g Ba(OH)2
n= m /M
n= 855/171 = 5moli Ba(OH)2
Explicație: