AJUTATI-MA VA ROG LA TESTUL 1!!! (APASATI PE IMAGINE CA SA SE VADA!)
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d)6/√3-√3=6√3/3-√3=2√3-√3=√3
2a)2√3(4√3-√6)-√18=8·3-2·3√2-3√2=24-9√2; b)(2√2-√3)(2/√3+√2)=(2√2-√3)×(2√3/3+√2)=(2√2-√3)(2√3+3√2)/3=(4√6+12-6-3√6)/3=(√6+6)/3
c)1/5√3=√3/15;1/√12=√3/6;3/2√3=√3/2;√75=5√3⇒
(√3/15-√3/6-√3/2)÷1/5√3=(2√3-5√3-15√3)/15×5√3=(-18√3/30)×5√3=-9
3 a=√3+√2;b=√3-√2
Ma=(a+b)/2=(√3+√2+√3-√2)/2=2√3/2=√3
Mg=√a×b=√(√3+√2)(√3-√2)=√(√3)²-(√2)²=√(3-2)=√1=1
4 -3√5=-6,7;-7=-7;-2√11=-6,6;-4√3=-6,9⇒-7>-4√3>-3√5>-2√11
5 a) I√3-√5I=√5-√3,deoarece:√5>√3;I2√5-3√3I=3√3-2√5,deoarece:2√5<3√3⇒
√5-√3+3√3-2√5=-√5+2√3
b)√(3√7-8)²+√(2√7-5)²=3√7-8+2√7-5=5√7-13