URGEENT!! Triunghiul dreptunghic ABC, m(∠A) = 90°, AD⊥BC, D ∈(BC), are AB/AC=3/4 si aria egala cu 216 cmp. Aflati: a) perimetrul triunghiului; b) lungimea inaltimii Ad; c) lungimile segmentelor BD si CD.
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AB*AC/2=216 AB*AC=108 AB=3*AC/4 3*AC*AC/4=108 AC=12 AB=9 BC*BC=144+81 BC*BC=225 BC=15 P=15+9+12 AD*DC/2+AD*DB/2=216 de aici faci tu ...! afli AD folosesti ca bc=dc+db si dupa th. lui pit.(cat*cat+cat*cat=ip*ip)
AB*AC=108
AB=3*AC/4
3*AC*AC/4=108
AC=12
AB=9
BC*BC=144+81
BC*BC=225
BC=15
P=15+9+12
AD*DC/2+AD*DB/2=216
de aici faci tu
...!
afli AD
folosesti ca bc=dc+db
si dupa th. lui pit.(cat*cat+cat*cat=ip*ip)