BD=DC=32/2=16 cm
In ΔADB(∡D=90°) Aplicam Teorema lui Pitagora (I²=C₁²+C₂²)
AB²=BD²+AD²
AB²=16²+12²
AB²=256+144
AB²=400
AB=√400
AB=20 cm
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BD=DC=32/2=16 cm
In ΔADB(∡D=90°) Aplicam Teorema lui Pitagora (I²=C₁²+C₂²)
AB²=BD²+AD²
AB²=16²+12²
AB²=256+144
AB²=400
AB=√400
AB=20 cm