Răspuns:

a)AB=√(xA-xB)²+(yA-yB)²

1.AB=√(3-(-1))²+(1-4)²=

√(3+1)²+(-3)²=√(4²+9)=√(16+9)=√25=4

2,AB=√(2-0)²+(0-3)²=√(2²+(-3))²=√(4+9)=√13

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b)Formula

AB: (y-yA)/(yB-yA)=(x-xA)/(xB-xA)

1.AB=(y-1)/(4-1)=(x-3)/(-1-3)

(y-1)/3=(x-3)/(-4)

y-1= -3/4(x-3)

y= -3x/4+9/4+1

y= -3x/4+13/4

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2.(y-0)/(3-0)=(x-2)/(0-2)

y/3=(x-2)/(-2)

y=-3/2(x-2)

y= -3x/2+3

Explicație pas cu pas: