Numitorul comun este n(n+1)(n+2)
impartim cele 2 relatii, a doua la prima si obtinem
n²(n+1)=144×4
n³+n²-576=0
n³-512+n²-64=0
n³-8³+n²-8²=0
(n-8)(n²+8n+64)+(n-8)(n+8)=0
(n-8)(n²+9n+72)=0
n=8
k=14 400
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Numitorul comun este n(n+1)(n+2)
impartim cele 2 relatii, a doua la prima si obtinem
n²(n+1)=144×4
n³+n²-576=0
n³-512+n²-64=0
n³-8³+n²-8²=0
(n-8)(n²+8n+64)+(n-8)(n+8)=0
(n-8)(n²+9n+72)=0
n=8
k=14 400