Un numar este cu 7 supra 180 mai mare decat 11 supra 36.aflati suma ce lor doua numere! ras final manual 0,65
finamihai
Noatm a=11/36 b=11/36+7/180=aducem la acelasi numitor=(11x5+7)/180=62/180=simplificam cu 2=31/90 deci b=31/90 a+b=11/36+31/90=(11x5+31x2)/180=117/180=0,65
b=11/36+7/180=aducem la acelasi numitor=(11x5+7)/180=62/180=simplificam cu 2=31/90
deci b=31/90
a+b=11/36+31/90=(11x5+31x2)/180=117/180=0,65