\sqrt{x {}^{2} + 2x - 8 } + \sqrt{ {x}^{2} - 6x + 8 } = 4 \sqrt{x - 2}x2+2x−8+x2−6x+8=4x−2.... Idea question from @jojoi54

July 2022 1 54 Report

\sqrt{x {}^{2} + 2x - 8 } + \sqrt{ {x}^{2} - 6x + 8 } = 4 \sqrt{x - 2}x2+2x−8+x2−6x+8=4x−2

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