Răspuns:
3x/2 =5y/3=2z/5=k → coeficient de proportionalitate
x=2/3k
y=3/5k
z=5/2k
x+y+z=226
¹⁰⁾2/3k+⁶⁾3/5k+¹⁵⁾5/2k=³⁰⁾226
20k+18k+75k=6780
113k=6780=>k=6780:113=>k=60
x=(2·60)/3=40
y=(3·60)/5=36
z=(5·60)/2=150
Sper ca ti-am fost de folos. Succes!!!
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Răspuns:
3x/2 =5y/3=2z/5=k → coeficient de proportionalitate
x=2/3k
y=3/5k
z=5/2k
x+y+z=226
¹⁰⁾2/3k+⁶⁾3/5k+¹⁵⁾5/2k=³⁰⁾226
20k+18k+75k=6780
113k=6780=>k=6780:113=>k=60
x=(2·60)/3=40
y=(3·60)/5=36
z=(5·60)/2=150
Sper ca ti-am fost de folos. Succes!!!