sa se determine xE R astfel incat tripletul urmator sa fie format din numere in prog geometrica :
4, 3+x , x2 + 5x + 4,25
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Din a,b,c termenii unei p.g ⇒ b = V(a*c)
3+x = V[4(x²+5x+4,25)]
3+x = V[4x²+20x+17] ridici toata ecuatia la a 2-a ca sa scapi de radical
4x²+20x+17 = 9+6x+x²
4x²-x²+20x-6x+17-9 = 0
3x²+14x+8 = 0
delta = 196 -96 = 100
x1 = (-14+10)/6 = -4/6 = -2/3
x2 = (-14-10)/6 = -24/6 = -4