Ms = 400 g HCl. c = 36,5 . ACl = 35,5. Sa se afla n CH4= ? Stiind formulele . C+2H2-->CH4. Zn+2HCl--.... Idea question from @Madalin4458

January 2019 1 94 Report

Ms = 400 g HCl.
c = 36,5 .
ACl = 35,5.
Sa se afla n CH4= ?
Stiind formulele .
C+2H2-->CH4.
Zn+2HCl-->H2+Zn+Cl2.

alicia892 C=md*100/ms
md = c*ms/100=36.5*400/100=146 g HCl
n=m/M=146/36.5=4 moli HCl

Zn+2HCl→H₂+Zn+Cl₂
2 moli HCl.......1 mol H₂
4 moli HCl.......x
x=4/2=2 moli H₂

C+2H₂→CH₄
2 moli H₂........1 mol CH₄
2 moli H₂.......y y=2/2=1 mol CH₄

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