AB=AC
BD=DE
BD⊥AC⇒ m(∡ADB)=90°⇒ AD⊥BE
D mijlocul lui BE⇒ AD mediana, dar AD inaltime⇒ ΔABE isoscel⇒ AB=AE=AC
m(∡CBD)=20°⇒ m(∡ACB)=180-(20+90)=70°=m(∡ABC)
m(∡BAC)=180-(70+70)=40°=m(∡EAD) (ΔABE isoscel)
m(∡BAE)=40+40=80°
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AB=AC
BD=DE
BD⊥AC⇒ m(∡ADB)=90°⇒ AD⊥BE
D mijlocul lui BE⇒ AD mediana, dar AD inaltime⇒ ΔABE isoscel⇒ AB=AE=AC
m(∡CBD)=20°⇒ m(∡ACB)=180-(20+90)=70°=m(∡ABC)
m(∡BAC)=180-(70+70)=40°=m(∡EAD) (ΔABE isoscel)
m(∡BAE)=40+40=80°