E(x))=[((x+3)/(x-3))²+1+(2x+6)/(x-3)](x-3)/4x-1=
aducem la același numitor parateza mare
[x²+6x+9+x²-6x+9+(2x+6)(x-3)]/(x-3)²×
(x-3)/4x-1=
(2x²+18+2x²-6x+6x-18)/[(x-3)×4x]-1=
4x²/[4x(x-3)]-1=x/(x-3)-1=[x-(x-3)]/(x-3)=
(x-x+3)/(x-3)=3/(x-3)
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E(x))=[((x+3)/(x-3))²+1+(2x+6)/(x-3)](x-3)/4x-1=
aducem la același numitor parateza mare
[x²+6x+9+x²-6x+9+(2x+6)(x-3)]/(x-3)²×
(x-3)/4x-1=
(2x²+18+2x²-6x+6x-18)/[(x-3)×4x]-1=
4x²/[4x(x-3)]-1=x/(x-3)-1=[x-(x-3)]/(x-3)=
(x-x+3)/(x-3)=3/(x-3)