Răspuns:
C
Explicație pas cu pas:
[tex]4 \sin^{2} (x) - 4 \sin(x) + 1 = 0 [/tex]
[tex] {(2 \sin(x) - 1)}^{2} = 0[/tex]
[tex]2 \sin(x) - 1 = 0 \implies \sin(x) = \frac{1}{2} \\ [/tex]
[tex] \iff x \in \Big\{ {( - 1)}^{k} \frac{\pi}{6} + k\pi \Big|k \in \mathbb{Z}\Big\}[/tex]
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Răspuns:
C
Explicație pas cu pas:
[tex]4 \sin^{2} (x) - 4 \sin(x) + 1 = 0 [/tex]
[tex] {(2 \sin(x) - 1)}^{2} = 0[/tex]
[tex]2 \sin(x) - 1 = 0 \implies \sin(x) = \frac{1}{2} \\ [/tex]
[tex] \iff x \in \Big\{ {( - 1)}^{k} \frac{\pi}{6} + k\pi \Big|k \in \mathbb{Z}\Big\}[/tex]