a) [3(x-2)-2(x-1)]
3(x−2)−2(x−1)
=x−4
b) [x(x+3)-x(x+2)+5]
x(x+3)−x(x+2)+5
=x+5
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a) [3(x-2)-2(x-1)]
3(x−2)−2(x−1)
=x−4
b) [x(x+3)-x(x+2)+5]
x(x+3)−x(x+2)+5
=x+5
Sper că te-am ajutat! :)