Răspuns:
f(x)=x²-2x-3
Punctul de minim
-b/2a=-(-2)/2=2/2=1
[-1,2]=[-1,1]U[1,2]
calculezi f([-1,1])
f(-1)=1+2-3=0
f(10=1-2-3=-4
f([-1,1])=[-4,0]
Calculezi f([1,2])=
f(1)=-4
f(2)=2²-2*2-3= -3
f([1,2])=[-4,-3]
f(-1,2)=[-4,0]U[-4,-3]=[-4,0]
Explicație pas cu pas:
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Răspuns:
f(x)=x²-2x-3
Punctul de minim
-b/2a=-(-2)/2=2/2=1
[-1,2]=[-1,1]U[1,2]
calculezi f([-1,1])
f(-1)=1+2-3=0
f(10=1-2-3=-4
f([-1,1])=[-4,0]
Calculezi f([1,2])=
f(1)=-4
f(2)=2²-2*2-3= -3
f([1,2])=[-4,-3]
f(-1,2)=[-4,0]U[-4,-3]=[-4,0]
Explicație pas cu pas: