#include <iostream>
#include <cmath>
using namespace std;
int main() {
double a, b, c;
cin >> a >> b >> c;
double p = (a + b + c) / 2;
double S = sqrt(p*(p-a)*(p-b)*(p-c));
cout << S;
return 0;
}
Explicatie:Aria unui triunghi oarecare se poate afla dupa urmatoarea formula:
[tex]S = \sqrt{p(p-a)(p-b)(p-c)}\\\\p = \frac{a+b+c}{2}[/tex]
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Ai rezolvarea in C++ mai jos
#include <iostream>
#include <cmath>
using namespace std;
int main() {
double a, b, c;
cin >> a >> b >> c;
double p = (a + b + c) / 2;
double S = sqrt(p*(p-a)*(p-b)*(p-c));
cout << S;
return 0;
}
Explicatie:
Aria unui triunghi oarecare se poate afla dupa urmatoarea formula:
[tex]S = \sqrt{p(p-a)(p-b)(p-c)}\\\\p = \frac{a+b+c}{2}[/tex]