Daca a,b,c sunt numere naturale astfel incat a+b+c=32 si 2 x a+b+2 x c=57, calculati (a+c)x(3 x a+2 x b+3 x c). Ajutor. Dau CORONITA...
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2a+b+2c=57
a+b+c+(a+c)=57
32+(a+c)=57
a+c=57-32=25
(a+c)x(3a+2b+3c)=
= (a+c)x[(2a+b+2c)+(a+b+c)]=
=25x(57+32)=
=25x89=2225