Răspuns:
nr.moli metan niu=V/Vm= 100 l/22,4 l/mol=4,46mol
11 moli metan,,,,,,,,1mol aspirina
4,46mol...................x
x=niu=0,40 mol aspirina-teoretic,la randament 100%
practic ,se va obtine mai putin
niu,practic=0,40x75/100 moli=0,30moli aspirina
masa de aspirina
m= niuxmiu= 0,30molix180g/mol=54,8g
Explicație:
Show life that you have a thousand reasons to smile
© Copyright 2024 DOKU.TIPS - All rights reserved.
Răspuns:
nr.moli metan niu=V/Vm= 100 l/22,4 l/mol=4,46mol
11 moli metan,,,,,,,,1mol aspirina
4,46mol...................x
x=niu=0,40 mol aspirina-teoretic,la randament 100%
practic ,se va obtine mai putin
niu,practic=0,40x75/100 moli=0,30moli aspirina
masa de aspirina
m= niuxmiu= 0,30molix180g/mol=54,8g
Explicație: