Răspuns:
MFe=56g/mol
MFe3O4=3x56+4x16=232g/mol
3x56g.................232g
3Fe + 4H2O → Fe3O4 + 4H2
16g...........................yg
y=16x232/3x56=22,09g Fe3O4
Explicație:
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Verified answer
Răspuns:
MFe=56g/mol
MFe3O4=3x56+4x16=232g/mol
3x56g.................232g
3Fe + 4H2O → Fe3O4 + 4H2
16g...........................yg
y=16x232/3x56=22,09g Fe3O4
Explicație: