Explicație:
a)calculam masa molară a CO2=12+2×16=44
1mol de CO2............conține 44g CO2
2moli CO2..............x g
[tex]x = \frac{2 \times 44}{1} = 88g[/tex]
b) masa de H2O=2+16=18g
1mol H2O........18g
ymoli H2O......360g
[tex]y = \frac{360}{18} = 20[/tex]
a)masa de H2O=18 g
1 mol.......18g
6 moli.......z g
[tex]z = 6 \times 18 = 108g[/tex]
b)masa de NaOH=23+16+1=40g
1mol........40g
v moli.......600g
[tex]v = \frac{600}{40} = 15[/tex]
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Explicație:
a)calculam masa molară a CO2=12+2×16=44
1mol de CO2............conține 44g CO2
2moli CO2..............x g
[tex]x = \frac{2 \times 44}{1} = 88g[/tex]
b) masa de H2O=2+16=18g
1mol H2O........18g
ymoli H2O......360g
[tex]y = \frac{360}{18} = 20[/tex]
a)masa de H2O=18 g
1 mol.......18g
6 moli.......z g
[tex]z = 6 \times 18 = 108g[/tex]
b)masa de NaOH=23+16+1=40g
1mol........40g
v moli.......600g
[tex]v = \frac{600}{40} = 15[/tex]