Răspuns:
[tex]1) {2}^{a} = {4}^{3} \\ { 2}^{a} =( {2}^{2} ) ^{3} \\ {2}^{a} = {2}^{6} \\ a = \\ varianta \: a \\ [/tex]
[tex]2)cazuri \: favorabile \: 21 \\ cazuri \: posibile \: 28 \\ p = \frac{cazuri \: favorabile}{cazuri \: posibile} = \frac{21}{28 } = \frac{3}{4} \\ varianta \: c[/tex]
[tex]3)2.3 - 2.0 = 0.3 \\ varianta \: c[/tex]
4)M10={0;10;20;30..}
varianta b
[tex] 5)x \times y = \sqrt{2} + 1 \times \frac{1}{ \sqrt{2} + 1 } = \frac{ \sqrt{2} + 1 }{ \sqrt{2} + 1} = 1 \\ varianta \: a \\ 6)8 + 1 + 10 = 19 \\ varianta \: a[/tex]
Show life that you have a thousand reasons to smile
© Copyright 2024 DOKU.TIPS - All rights reserved.
Răspuns:
[tex]1) {2}^{a} = {4}^{3} \\ { 2}^{a} =( {2}^{2} ) ^{3} \\ {2}^{a} = {2}^{6} \\ a = \\ varianta \: a \\ [/tex]
[tex]2)cazuri \: favorabile \: 21 \\ cazuri \: posibile \: 28 \\ p = \frac{cazuri \: favorabile}{cazuri \: posibile} = \frac{21}{28 } = \frac{3}{4} \\ varianta \: c[/tex]
[tex]3)2.3 - 2.0 = 0.3 \\ varianta \: c[/tex]
4)M10={0;10;20;30..}
varianta b
[tex] 5)x \times y = \sqrt{2} + 1 \times \frac{1}{ \sqrt{2} + 1 } = \frac{ \sqrt{2} + 1 }{ \sqrt{2} + 1} = 1 \\ varianta \: a \\ 6)8 + 1 + 10 = 19 \\ varianta \: a[/tex]