Aflati coord punctului de intersectie ale graficelor functiilor:f:R->R,f(x)=2x-1 si g:R->R,g(x)=x²-2x+3.Clasa a 9 a ,ajutorrr.Dau coroana ,puncte,inima,5 stele.
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Răspuns:
Rezolvi ecuatia f(x)=g(x)
x²-2x+3=2x-1
x²-2x+3-2x+1=0
x²-4x+4=0
(x-2)²=0
x-2=0
x=2
f(2)=2*2-1=4-1=3
A(2,3)
Explicație pas cu pas: