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ultima cifra a puterilor lui 3 se repeta dupa 4 pasi
2003 : 4 = 500 rest 4
U (2^2003) = U (2^3) = 8
U (3^2003) = U (3^3) = 7
U (7^2003) = U (7^3) = 3
U (4^2003)=4
S = > 8+7+3+4=22 , deci ultima cifra va fi 2