Răspuns:
x+y=67
(x-10)/y=0,5
prod mezilor=produsul extremilor intr o proporție
0,5y=x-10
x=0,5y+10
introducem ec.2 in prima
0,5y+10+y=67
1,5y=67-10=57
y=57/1,5=38
x=(38/2)+(10)=19+10=29
38,29 rationale
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Răspuns:
x+y=67
(x-10)/y=0,5
prod mezilor=produsul extremilor intr o proporție
0,5y=x-10
x=0,5y+10
introducem ec.2 in prima
0,5y+10+y=67
1,5y=67-10=57
y=57/1,5=38
x=(38/2)+(10)=19+10=29
38,29 rationale