1.descompuneti nr 390 in nr direct proportionale cu 3,4,6
2.descompuneti nr 420 in nr invers proportionale cu 2,8,4
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Răspuns:
1.
a/3 = b/4 = c/6 = k
a=3k
b=4k
c=6k
13k=390 =>k=30
a=90
b=120
c=180
2.
2a=8b=4c=k
a = k/2
b = k/8
c = k/4
4k+k+2k=420×8
7k=420×8
k=480
a=240
b=60
c=120