Calculati (2+i)(3-2i)-(1-2i)(2-i)
flavistin
(2+i)(3-2i)-(1-2i)(2-i)=8+4i
2 votes
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raluca98t
(2+i)(3-2i) - (1-2i)(2-i) = (6-4i+3i-2i²) - (2-i-4i+2i²) = 6-i+2 - (2-5i-2) = 8-i+5i = 8+4i
3 votes
Thanks 2
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