Sorunun çözümü şu şekildedir:
[tex]({{ cosx(1-sinx) \over (1 + sinx)(1-sinx) } + {(1 + sinx)(cosx) \over (cosx)(cosx)}}) . {cosx}\\\\= ({{cosx- sinx.cosx} \over {cos^2x}} + {{sinx.cosx+cosx \over cos^2x}}). {cosx}\\\\= ({2cosx \over cos^2x}). {cosx}\\\\= 2[/tex]
İyi dersler!
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Sorunun çözümü şu şekildedir:
[tex]({{ cosx(1-sinx) \over (1 + sinx)(1-sinx) } + {(1 + sinx)(cosx) \over (cosx)(cosx)}}) . {cosx}\\\\= ({{cosx- sinx.cosx} \over {cos^2x}} + {{sinx.cosx+cosx \over cos^2x}}). {cosx}\\\\= ({2cosx \over cos^2x}). {cosx}\\\\= 2[/tex]
İyi dersler!