7^(11+12+13+...+30)=(7^n)^3*49.... Idea question from @Paidus

December 2018 1 405 Report

7^(11+12+13+...+30)=(7^n)^3*49

MFM 7^(11+12+.+30)=7^3n.7²=7^(3n+2)
11+12+............+30=(11+30).20/2=410
7^410=7^(3n+2)
ca sa fie egale trebuie ca
3n+2=410
3n=410-2=408
n=408:3=136
n=136

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