Răspuns:
[tex]7x = 11y = > x = \frac{11y}{7} [/tex]
[tex] \frac{3 \times \frac{11y}{7} + 2y}{5 \times \frac{11y}{7} - 7y} = \frac{ \frac{47y}{7} }{ \frac{6y}{7} } = \frac{47}{6} [/tex]
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Răspuns:
[tex]7x = 11y = > x = \frac{11y}{7} [/tex]
[tex] \frac{3 \times \frac{11y}{7} + 2y}{5 \times \frac{11y}{7} - 7y} = \frac{ \frac{47y}{7} }{ \frac{6y}{7} } = \frac{47}{6} [/tex]